Deflection equation using Macaulay's

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The discussion focuses on calculating the deflection equation for a beam subjected to specific loads and material properties. Key issues identified include the incorrect starting point for the uniformly distributed load (UDL) and errors in the integration of bending moment equations. The calculated deflections were found to be excessively large, indicating potential errors in the calculations or assumptions made. It was noted that the beam's bending stresses exceeded the elastic limit for steel, suggesting failure under the given conditions. The conversation emphasizes the importance of ensuring small slope approximations in elastic beam theory for accurate deflection calculations.
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Homework Statement


BEAM.PNG


I need to calculate the deflection equation.
R1=33kN
R2=32kN
E=210GPa
calculated I=5.4*10^-7 m^4

Homework Equations

The Attempt at a Solution


equation.PNG


Is the equation correct? I'm not sure if I got the u.d.l. right.
 
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sponsoraw said:

Homework Statement


View attachment 83515

I need to calculate the deflection equation.
R1=33kN
R2=32kN
E=210GPa
calculated I=5.4*10^-7 m^4

Homework Equations

The Attempt at a Solution


View attachment 83516

Is the equation correct? I'm not sure if I got the u.d.l. right.
Indeed, there is a problem with the UDL. The UDL starts at x = 0, whereas your BM equation has it starting at x = 2 m.

Also, for completeness, I would add a term for the reaction R2 located at x = 5 m, even though this would not affect any values calculated by the BM expression.
 
Sorry for the late reply. My current solution is attached.
 

Attachments

sponsoraw said:
Sorry for the late reply. My current solution is attached.
I noticed several things which need fixing.

1. In your expression for the BM, you have EI y" = 103[Mess].
When you integrate to find the slope, you wind up with EI y' = 103[Mess + A] and EI y = 103[Mess + Ax + B].
There's really no need to bring the constants of integration inside the brackets where the other terms are multiplied by 1000 due to the loading of the beam.

2. When you integrated the terms for the UDL, the expression -5x2 became -1.67x3 and then -0.56x4. I think -1.67 / 4 ≠ -0.56.
This same error pops up in the term which cuts off the UDL.

You should look at your deflections again, particularly checking the calculation of A and B. The magnitudes of your calculated deflections (one the order of 0.5 m) seem rather large given the length of this beam. Make sure you haven't misplaced a decimal somewhere.
 
Thanks, in that case one more time! I've corrected the 0.56 to 0.4175 and the value of A is now A=-75.878. Those changes however made the deflection even greater. I've checked everything a couple of times now and I can't see where I when wrong. I've attached the full calcs again. I'm a bit stuck now.
 

Attachments

sponsoraw said:
Thanks, in that case one more time! I've corrected the 0.56 to 0.4175 and the value of A is now A=-75.878. Those changes however made the deflection even greater. I've checked everything a couple of times now and I can't see where I when wrong. I've attached the full calcs again. I'm a bit stuck now.

I double checked your deflection calculations, and they are correct, but for a few round off errors. What you have as 0.4175 should be 0.4167, and I get A = -76.00.

Now that you have included the dimensions of the cross section of the beam, I can see why the deflections are so large. The max. bending stresses for the beam are way beyond the elastic limit for steel (whose E = 210 GPa) and are the same order of magnitude as E. This suggests that a real beam made of steel loaded and supported as shown in the OP would have failed completely.

In order for the equation M/EI = y" to be valid, the slope of the beam must be small, such that θ << 1, which is not the case here. While this beam is a good exercise for showing how to calculate deflection using McCauley's Method, it is a terrible choice because its deflections are much too large to satisfy the small slope approximation on which elastic beam theory is based.
 
Thanks for your help on that, it took a wee while. I shall round up all calcs to 4 d.p. for a better accuracy.
 

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