Deflection of a Beam using Double Integration

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SUMMARY

The discussion focuses on calculating the maximum deflection of a simply supported beam using the double integration method, where the beam experiences two equal and opposite concentrated couples (C) spaced a distance (a) apart. The boundary conditions are defined as v=0 at x=0 and v=0 at x=3a, with the maximum deflection occurring at x=(3/2)a. The correct moment function M(x) is established as M(x)=0 for 0 PREREQUISITES

  • Understanding of beam mechanics and deflection principles
  • Familiarity with the double integration method for beam deflection
  • Knowledge of boundary conditions in structural analysis
  • Proficiency in calculating shear and moment diagrams
NEXT STEPS
  • Study the double integration method for beam deflection in detail
  • Learn how to derive moment functions for various loading conditions
  • Explore shear and moment diagrams for complex beam configurations
  • Review boundary condition applications in structural analysis
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Structural engineers, civil engineering students, and professionals involved in beam analysis and design will benefit from this discussion.

voodoonoodle
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Homework Statement



Need to determine the maximum deflection of the beam, by using double integration, and EI is constant.

...>...<
_______(_______)_______
^........o
|<--a-->|<--a-->|<--a-->|

Tried to draw this the best I could. It is a simply supported beam, with a concentrated couples of equal value (C) but opposite direction, with a distance between of (a).

Homework Equations



I pretty sure that my boundary conditions are: v=0 @ x=0 and v=0 @ x=3a

and my max. deflection will occur at x=(3/2)a

The Attempt at a Solution



My problem is that I don't know how to get started, all the examples show only one concentrated moment. I'm assuming I have no reactions, because when I sum the moments around either side, the moments cancel out.

I have tried using that M=C(x-a) and that didn't come out correct. So basically I'm looking for help in trying to get the moment function.

I have also tried M=C where I get the following

slope as a function of x = Cx/EI + C1
deflection as a function of x = Cx^2/2EI + C1x + C2

boundary conditions:
v=0 @ x=0 so C2 = 0
v=0 @ x=3a so C1 = (-3(C)(a))/(2EI)

so then I come up with an answer of (-9(C)(a^2))/(8EI) for the max deflection using x=(3/2)a
 
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Well, it's been way too long since I used the double integration method, but it does bring back some haunting memories. If you're looking at y" =M(x)/EI, my suggestion would be to calculate M(x) using shear and moment diagrams. Looks to me like you've got no shear at all anywher along the beam, and just a constant moment of c in between the two applied couples, and no moment on either side of those couples to the support points.
 
PhantomJay, that is correct. I'm just not sure how to come up with M(x). I have tried several things for it but still can't get the answer they give for Max Deflection. Which I know to be (5(C)(a^2))/(8EI).
 
voodoonoodle said:
PhantomJay, that is correct. I'm just not sure how to come up with M(x). I have tried several things for it but still can't get the answer they give for Max Deflection. Which I know to be (5(C)(a^2))/(8EI).
Well, M(x) =0 between 0 and a; M(x) = C between a and 2a; and M(x) = 0 between 2a and 3a. Now double integrate and use proper boundary conditions , which is probably what you're trying to do. I think the key is to deternine the boundary conditons. I've been relying on tables and charts, so my calculus is a bit rusty at this point.
 
What a coincidence, I found this post: http://forums.mathalino.com/general-engineering-sciences/strength-of-materials/beam-deflection-by-double-integration-method" . It is exactly the same problem as this one.
 
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