Deflection of a Beam using Double Integration

AI Thread Summary
The discussion focuses on calculating the maximum deflection of a simply supported beam subjected to two equal but opposite concentrated couples. The user is unsure how to derive the moment function M(x) due to the unique loading condition, as previous examples only involved single moments. They have established boundary conditions and attempted to apply the double integration method but are struggling to achieve the correct maximum deflection value. Another user suggests determining M(x) through shear and moment diagrams, indicating that M(x) is zero in certain intervals and constant in others. The correct maximum deflection is noted to be (5(C)(a^2))/(8EI), emphasizing the importance of accurate moment calculations.
voodoonoodle
Messages
2
Reaction score
0

Homework Statement



Need to determine the maximum deflection of the beam, by using double integration, and EI is constant.

...>...<
_______(_______)_______
^........o
|<--a-->|<--a-->|<--a-->|

Tried to draw this the best I could. It is a simply supported beam, with a concentrated couples of equal value (C) but opposite direction, with a distance between of (a).

Homework Equations



I pretty sure that my boundary conditions are: v=0 @ x=0 and v=0 @ x=3a

and my max. deflection will occur at x=(3/2)a

The Attempt at a Solution



My problem is that I don't know how to get started, all the examples show only one concentrated moment. I'm assuming I have no reactions, because when I sum the moments around either side, the moments cancel out.

I have tried using that M=C(x-a) and that didn't come out correct. So basically I'm looking for help in trying to get the moment function.

I have also tried M=C where I get the following

slope as a function of x = Cx/EI + C1
deflection as a function of x = Cx^2/2EI + C1x + C2

boundary conditions:
v=0 @ x=0 so C2 = 0
v=0 @ x=3a so C1 = (-3(C)(a))/(2EI)

so then I come up with an answer of (-9(C)(a^2))/(8EI) for the max deflection using x=(3/2)a
 
Last edited:
Physics news on Phys.org
Well, it's been way too long since I used the double integration method, but it does bring back some haunting memories. If you're looking at y" =M(x)/EI, my suggestion would be to calcualte M(x) using shear and moment diagrams. Looks to me like you've got no shear at all anywher along the beam, and just a constant moment of c in between the two applied couples, and no moment on either side of those couples to the support points.
 
PhantomJay, that is correct. I'm just not sure how to come up with M(x). I have tried several things for it but still can't get the answer they give for Max Deflection. Which I know to be (5(C)(a^2))/(8EI).
 
voodoonoodle said:
PhantomJay, that is correct. I'm just not sure how to come up with M(x). I have tried several things for it but still can't get the answer they give for Max Deflection. Which I know to be (5(C)(a^2))/(8EI).
Well, M(x) =0 between 0 and a; M(x) = C between a and 2a; and M(x) = 0 between 2a and 3a. Now double integrate and use proper boundary conditions , which is probably what you're trying to do. I think the key is to deternine the boundary conditons. I've been relying on tables and charts, so my calculus is a bit rusty at this point.
 
What a coincidence, I found this post: http://forums.mathalino.com/general-engineering-sciences/strength-of-materials/beam-deflection-by-double-integration-method" . It is exactly the same problem as this one.
 
Last edited by a moderator:
Back
Top