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[tex]\int^{\infty}_{-\infty} f(x)\delta(x-x_0)dx[/tex]

Where

[tex]f(x)=ln(x+3), x_0=-2[/tex]

Ordinarily, you would just evaluate [tex]f(x_0)[/tex], so it would be 0, but in this case, since [tex]f(x)[/tex] is [tex]-\infty[/tex] at [tex]x=-3[/tex], does that make a difference?

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# Delta function integral

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