Density of chromium ions in ruby

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Homework Help Overview

The discussion revolves around estimating the density of chromium ions in ruby, given a concentration of chromium at 0.05% by weight. Participants are examining the implications of this concentration on density calculations and addressing potential errors in the original poster's approach.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are analyzing the calculation of chromium density based on its weight percentage in ruby and questioning the treatment of the percentage in the calculations. There is also a discussion about the need for the atomic mass of chromium in the calculations.

Discussion Status

Some participants have pointed out discrepancies in the calculations related to the percentage of chromium, while others have confirmed the need for the atomic mass in the density estimation. There is an ongoing exploration of the calculations, with no clear consensus on the correct approach yet.

Contextual Notes

Participants are working under the assumption that the concentration of chromium is accurately stated as 0.05% by weight, and there is a focus on the implications of this assumption in the calculations. The decay rate mentioned appears to be unrelated to the primary problem.

lcr2139
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Homework Statement


estimate the density of chromium ions in ruby, assuming that the concentration of chromium in ruby is about 0.05% by weight.

Homework Equations


decay rate = 0.5x10^3 s^-1
answer: density N (sub T)= 1.6x10^19 cm^-3

The Attempt at a Solution


density = mass/volume
density of ruby = 4.02 g/cm^3
density of chromium = (4.02)(0.05) = .201 g/cm^3
I know that this is wrong!
What do I do?
 
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It says "0.05%". Did you mean that or 5%?
 
Yes, I really meant 0.05%.
 
lcr2139 said:
Yes, I really meant 0.05%.
But your calculation treated it as 5%.
I believe you will also need the atomic mass of chromium.
 
haruspex said:
But your calculation treated it as 5%.
I believe you will also need the atomic mass of chromium.

0.5*10^-3 = .0005 which = .05%

lcr2139 treated it properly in the calculation (not to say that I have any idea what the calculation is, only that I know that 0.5*10^-3 = .05%)
 
ChuckB said:
0.5*10^-3 = .0005 which = .05%
lcr2139 treated it properly in the calculation (not to say that I have any idea what the calculation is, only that I know that 0.5*10^-3 = .05%)
The 0.5*10-3 was quoted as a decay rate, with the right units for that, which has nothing to do with the problem. (In fact, lcr wrote 103, not 10-3., but minus seems more likely for a decay rate.)
In the calculation, lcr used 5% here:
lcr2139 said:
density of ruby = 4.02 g/cm^3
density of chromium = (4.02)(0.05) = .201 g/cm^3
 
Last edited:
density of ruby: 4.02 g/cm^3
molecular weight of chromium: 52 g/mol

(4.02g/cm^3)*(.0005)*(6.022*10^23 atoms/mol) / (52 g/mol) = 2.32*10^19 cm^-3

This is wrong! The real answer is NsubT= 1.6 * 10^19 cm^-3

where am I going wrong?
 
lcr2139 said:
density of ruby: 4.02 g/cm^3
molecular weight of chromium: 52 g/mol

(4.02g/cm^3)*(.0005)*(6.022*10^23 atoms/mol) / (52 g/mol) = 2.32*10^19 cm^-3

This is wrong! The real answer is NsubT= 1.6 * 10^19 cm^-3

where am I going wrong?
Your calculation looks right to me.
 

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