Derivation of Laplace in spherical co-ordinates

darwined
Messages
18
Reaction score
0
I have been trying to derive the Laplace in spherical co ordinates.
I have attached a file which has basic equations.
I am trying to get the following equation.

d(phi)/dx= -sin(phi)/(r sin (theta)).

I have also attached the materials I am referring to.
Can someone please help me derive the equation.

Thank you.
 

Attachments

  • Laplac.jpg
    Laplac.jpg
    3.7 KB · Views: 507
  • derivation of the Laplacian from.pdf
    derivation of the Laplacian from.pdf
    182.6 KB · Views: 863
  • The Laplacian Operator from Cartesian to Cylindrical to Spherical Coordinates.pdf
    The Laplacian Operator from Cartesian to Cylindrical to Spherical Coordinates.pdf
    316.7 KB · Views: 635
Physics news on Phys.org
This is a pretty cumbersome way. The most easy is to use the action principle. The action
A[\phi]=\int \mathrm{d}^3 \vec{x} [(\vec{\nabla} \phi)^2+f \phi]
leads to the equation
\Delta \phi=f.
Now you write the gradient in terms of spherical coordinates (which is easy to derive by your direct method)
\vec{\nabla} \phi=\vec{e}_r \partial_r \phi+\frac{1}{r} \vec{e}_{\theta} \partial_{\theta} \phi + \frac{1}{r \sin \theta} \vec{e}_{\varphi} \partial_{\varphi} \phi.
The volume element is
\mathrm{d}^3 {\vec{r}}=\mathrm{d} r \mathrm{d} \theta \mathrm{d} \varphi r^2 \sin \theta.
This you plug into the action integral and use the Euler-Lagrange equations to derive the field equation in terms of spherical coordinates. This leads to the Laplacian by identifying it with f[/tex].
 
darwined said:
I have been trying to derive the Laplace in spherical co ordinates.
I have attached a file which has basic equations.
I am trying to get the following equation.

d(phi)/dx= -sin(phi)/(r sin (theta)).

I have also attached the materials I am referring to.
Can someone please help me derive the equation.

Thank you.
Show us your attempt at deriving that equation.
 
I second Vela. Vanhees is focusing on ##\Delta##. If you want a hint for your ## {d\phi \over dx} ## question: ##\tan \phi = {y \over x} ## is a good starting point.
 
Thank you for your reply vanhees71. But I am not sure how you even got the equation.

A[ϕ]=∫d3x→[(∇→ϕ)2+fϕ]

I am a beginner trying to learn this derivation.

Thank you BvU, your idea helped.

Thank you all.
 
Your attached references are just a straightforward transformation of coordinates that you learn how to do in a course on partial differential equations. Have you had a course that covers partial differential equations yet?

Chet
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top