Derivative of a Quadratic Function: Understanding the Use of cis(x)

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Homework Statement



Hi,

My teacher marked me wrong when I was asked to find the derivative of
-x^2 - 2x + 8
it was a review for the AP test were we just review everything
and I put
2cis(pi)x - 2
she marked it wrong and put a question mark over cis(pi)...

What's up with this teacher?
Do you think if I used the sis function on the AP test they would mark it wrong? It's not wrong at all...

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The Attempt at a Solution

 
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I mean technically
x - 2 = x + (-1)2 = x + cis(pi)2
 
It's high school, so your teacher is probably unfamiliar with \mathrm{cis}(\theta). For the AP test, I'd recommend you stick to \frac{d}{dx}( -x^2-2x+8) = -2x-2.

I like it, though. :smile:
 
So is there no such thing as a negative number at all sense every negative number is really just cis(pi) times a positive number? Is that why
x - 2
is really just
x + (-1)2
I always thought that was a strange property myself, simply just change the sign to positive and multiple 2 by (-1)...
 
No, the existence of the cis function does not imply that there are no negative numbers. cis(pi) evaluates to a negative number, so you are just writing a negative number as a product of a positive number and -1.
 
At least write ei π
writing cis is just silly
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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