Derivative of Composite Trigonometric Functions

kxpatel29
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Homework Statement


What is the derivative of f(x) = cos^5(sin(8x))



Homework Equations


trig, product rule, chain rule



The Attempt at a Solution


f(x) = cos^5(sin(8x))

Answer: 5-sin^4(cos(8x))(8)
 
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kxpatel29 said:

Homework Statement


What is the derivative of f(x) = cos^5(sin(8x))



Homework Equations


trig, product rule, chain rule



The Attempt at a Solution


f(x) = cos^5(sin(8x))

Answer: 5-sin^4(cos(8x))(8)
You're close. f'(x) = 5cos4(sin(8x))*cos(8x)*8
This is the same as 40cos(8x)sin4(sin(8x))
 
Wait, isn't it

<br /> f&#039;(x) = -40\cos^4(\sin(8x)) \cdot \sin(\sin(8x)) \cdot \cos(8x)<br />
?

Because

<br /> \frac{d}{dx} (\cos(\sin(8x))^5 = 5(\cos(\sin(8x))^4 \cdot \frac{d}{dx}(\cos(\sin(8x)) = 5(\cos(\sin(8x))^4 \cdot -\sin(\sin(8x)) \cdot \frac{d}{dx}(\sin(8x)) = -5(\cos(\sin(8x))^4 \cdot \sin(\sin(8x)) \cdot 8 \cos(8x)<br />
<br /> = -40(\cos(\sin(8x))^4 \cdot \sin(\sin(8x)) \cdot \cos(8x) = -40\cos^4(\sin(8x)) \cdot \sin(\sin(8x)) \cdot \cos(8x)<br />

Or is your answer somehow equivalent to this?
 
spamiam said:
Wait, isn't it

<br /> f&#039;(x) = -40\cos^4(\sin(8x)) \cdot \sin(\sin(8x)) \cdot \cos(8x)<br />
?
No. You should not have a factor of sin(sin(8x)).

The original function is a composite of three functions: g(h(k(x))), where g(x) = x5, h(x) = sin(x), and k(x) = 8x.

f'(x) = g'(h(k(x)) * h'(k(x)) * k'(x)
spamiam said:
Because

<br /> \frac{d}{dx} (\cos(\sin(8x))^5 = 5(\cos(\sin(8x))^4 \cdot \frac{d}{dx}(\cos(\sin(8x)) = 5(\cos(\sin(8x))^4 \cdot -\sin(\sin(8x)) \cdot \frac{d}{dx}(\sin(8x)) = -5(\cos(\sin(8x))^4 \cdot \sin(\sin(8x)) \cdot 8 \cos(8x)<br />
<br /> = -40(\cos(\sin(8x))^4 \cdot \sin(\sin(8x)) \cdot \cos(8x) = -40\cos^4(\sin(8x)) \cdot \sin(\sin(8x)) \cdot \cos(8x)<br />

Or is your answer somehow equivalent to this?
 
Okay, either I'm being really thick or one of us is misreading the question.

kxpatel29 said:

Homework Statement


What is the derivative of f(x) = cos^5(sin(8x))

f(x) = cos^5(sin(8x)) = (cos(sin(8x)))^5.

Then f is the composition of 4 functions namely A(x) = x5, B(x) = cos(x), C(x) = sin(x), and D(x) = 8x.

Then f(x) = A(B(C(D(x)))).

And just to further persuade you, see attached.
 

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