Derivative of f: Finding the Derivative of \sqrt{x}(2x-7)

[Dantes]

Find the derivative of f when :

\sqrt{x}(2x-7)

When put into product rule form (following (f '*g) + (f*g') )

(\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)

Just started today making sure I am on the right track.

 

[justinbaker]

i am pretty sure this is actually the answer when in product rule

(\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)

 

[Dantes]

i am pretty sure this is actually the answer when in product rule

(\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)

Ahh yes...My fault doubled it twice.. thanks.

 

[Dantes]

hmm my fundamentals are screwed up, I forgot what happens here for the most part. with the fraction exponents and the radicals.

Factor the (\frac{1}{2}x^\frac{-1}{2}) into the (2x+7) ?