Derivative of Fraction using power rule

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Homework Help Overview

The problem involves finding the derivative of the function f(x) = 3 - 3/5x. Participants are discussing the application of the power rule and the treatment of constants in differentiation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine whether the derivative is zero due to the constant term or if it should be calculated using the power rule. Some participants question the interpretation of the function's format, seeking clarification on the expression.

Discussion Status

There is an ongoing discussion with various interpretations of the function. Some participants have offered guidance on applying the power rule, while others emphasize the importance of not providing direct solutions. The conversation reflects a mix of attempts to clarify the problem and share insights without reaching a consensus.

Contextual Notes

Participants are navigating the norms of the forum, with reminders about the purpose of guiding rather than solving directly. There is an acknowledgment of the learning process for newer members.

Phyzwizz
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The problem:
f(x)=3-3/5x

So I'm perfectly fine with finding the derivatives with stuff but I wasn't sure about this one. Would this be 0 because there is a three in the numerator and no x?
Or would it be 3-1/51-1=3-1=2?
 
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Sorry, is that f(x) = 3 - \frac35 x or f(x) = 3 - \frac3{5x}?
 
f(x)=3−3/5x
The derivative of 3 is going to be zero because its a constant.
Bring the x to the numunator.

Then you get 3x^-1/5. Apply the power rule
You get:

(-1)3x^-1-1/5 = -3x^-2/5

Now rewrite with positive exponants:

f'(x)= 3/5x^2
 
Thanks, that was pretty easy!
 
Hi Windowmaker. The point of these forums is to help guide people to the solution, not to do it for them.
 
I aplogize, I am new here. I won't make that mistake in the future!
 
Last edited:
No problem. I made that mistake when I was new too. Have fun and enjoy the forums.
 

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