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BUConsul
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So, Iv'e been doing a little bit of prestudying for the Complex Variables/Analysis calss that I'm taking in the Spring and Iv'e just finished learning about complex derivatives. So, the Caughy-Riemann equations harmonivs functions and the like. I also learned about diffrentiability (in the Complex Plane) and holomorphicity. So I was doing the HW in the back of the chapter and I wasn't able to do one of the problems.
Find if f'(z) exists, and if it does state at which points is it differntiable and where is it holomorphic and find f'(z)
I. f(z)=Im(z )
I. f(z)=Im(z)=f(x,y)=Im(x+iy)=y, fx= 0, fy=1 By Cuachy-Reimann we have that f'(z) exists for all points that satisfy fx=-ify Subbing in: 0 = -i(1) -> Since there exists no x,y in R that satisfies the given equations f(z) is nowhere differentiable. But the solution in the back of the book says: "didifferentiable at 0 with derivative 0, nowhere holomorphic". I'm a bit confused here, and I would greatly appreciate any help, I noticed that f:C -> R and was wondering if that had anything to do with the solution.
Find if f'(z) exists, and if it does state at which points is it differntiable and where is it holomorphic and find f'(z)
I. f(z)=Im(z )
I. f(z)=Im(z)=f(x,y)=Im(x+iy)=y, fx= 0, fy=1 By Cuachy-Reimann we have that f'(z) exists for all points that satisfy fx=-ify Subbing in: 0 = -i(1) -> Since there exists no x,y in R that satisfies the given equations f(z) is nowhere differentiable. But the solution in the back of the book says: "didifferentiable at 0 with derivative 0, nowhere holomorphic". I'm a bit confused here, and I would greatly appreciate any help, I noticed that f:C -> R and was wondering if that had anything to do with the solution.