1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Derivative of Lx^2+Ly^2+Lz^2 =?

  1. Feb 19, 2014 #1
    Thanks for your helpings...
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Feb 19, 2014 #2

    DrClaude

    User Avatar

    Staff: Mentor

    In ##L_x##, it should be ##\cos \phi##, not ##\cot \phi##. ##L_z## has the wrong sign.
     
  4. Feb 19, 2014 #3
    So how can i go on. In no way i coulnd't tackled it. Thanks for your help....
     
  5. Feb 19, 2014 #4

    DrClaude

    User Avatar

    Staff: Mentor

    Not sure what you mean here.

    Can you describe the problem you want to solve? The title of the thread is not very clear, do you mean you need to write ##L_x^2 + L_y^2 + L_z^2## in spherical coordinates ##(\theta, \phi)##?
     
  6. Feb 19, 2014 #5
    yes. just as you said.
     
  7. Feb 20, 2014 #6

    DrClaude

    User Avatar

    Staff: Mentor

    Then you need to calculate each term by applying it to itself, e.g.,
    $$
    L_z^2 = L_z L_z = -i \hbar \frac{\partial}{\partial \phi} \left( -i \hbar \frac{\partial}{\partial \phi} \right)
    $$
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Derivative of Lx^2+Ly^2+Lz^2 =?
  1. 2 equations 2 unknowns (Replies: 9)

Loading...