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y= 6^3x-7

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(x^2)-x

Read: Y equals 6 to the 3x minus 7 OVER/Divided by x to the 2nd minus x

Now I thought I had to do a quotient rule there and start by doing:

(x^2-x)(e^(ln6)(3x-7))(3) and then so on from there. I just don't know what to do with that 6 to the 3x-7. Is it something to do with "e"?

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# Derivatives of Exponential Functions Question

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