Find the derivative of:
[itex]2. f(x)=∫cos(5x)sin(5t)dt[/itex] when the integral is from 0 to x
Chain rule, dy/dx=dy/du*du/dx
The Attempt at a Solution
For the first one, I can just take 5x^3 as u and then apply the chain rule to get
but maple TA keeps telling me that it's incorrect...
As for the second one, I'm not sure how to approach something like that when x is actually in the integral, as in the cos(5x). I mean, when I'm applying the chain rule...do I have to include cos in my choice of u?