MHB Derive a Generalised Formula for c-d with Respect to θ

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In the discussion, the relationship between the sides of a right triangle is explored, specifically focusing on the projection of side b, denoted as d, in relation to the angle θ. It is established that when θ equals 0, side b equals side c, and when θ equals 90, side d equals 0. The goal is to derive a generalized formula for the difference c - d as a function of θ. The conversation emphasizes using trigonometric functions to express the ratio of d to b. A clear formula will help in understanding the geometric relationships in the triangle.
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In the above given triangle when θ = 0 then b=c
But when θ = 90 then d=0
Since d is the projection of b
How we can derive a generalised formula for d or c-d with respect to θ
Plese may kindly be elaborated
 

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Hello and welcome to MHB! (Wave)

Look at the right triangle, having side lengths $b,\,d,\,h$. Using a trigonometric function, what is the ratio of $d$ over $b$?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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