Derive conservation of center of mass position

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SUMMARY

The discussion focuses on the derivation of the conservation of center of mass (CoM) position in a system involving a mass, m, on a frictionless boat of mass M. When mass m is moved from one end of the boat to the other, the boat shifts in the opposite direction to maintain the CoM position, as described by the equation $$\frac{x_1\,m+x_2\,M}{m+M} = \frac{\tilde{x_1}\,m+\tilde{x_2}\,M}{m+M}$$. This principle is rooted in the conservation of momentum, where the total momentum of the system remains zero when external forces are absent, as stated by Newton's second law. The momentum of the system, represented as p, confirms that the CoM position remains unchanged during the motion of mass m.

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Jonsson
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Hello there,

If a mass, m, is placed at one end of an boat of mass M, which is located on a frictionless ocean. If the mass, m, is moved from one end of the boat to the other end, conservation of center of mass position ensures that the boat shifts a small distance in the opposite direction. The conservation of mass is given by: $$\frac{x_1\,m+x_2\,M}{m+M} = \frac{\tilde{x_1}\,m+\tilde{x_2}\,M}{m+M}$$ where each x equal the position of the masses.

How can I derive this formula from more fundamental physics?

Thank you for your time,

Kind regards,
Marius

PS: how can I most easily do inline latex? Is it possible to do something similar to $expr$? Thanks
 
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This has to do with conservation of momentum. You can show that for the system as a whole to have 0 momentum throughout the motion of the mass m, the center of mass position must not move. This assumes that the external forces are 0 and so by Newton's second law dp/dt=0, and in a frame where p(t=0)=0, dp/dt=0 for all t implies p(t)=0 for all t.

In the above, p stands for the momentum of the entire object (m+M). From this it can be derived that the CoM position must not move because p=(m+M)V_CoM.
 
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