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Derive integral of sqrt(x^2-a^2)

  1. Dec 5, 2008 #1
    Sorry me again

    THE CRC tables define the above integral as

    using sqrt(x^2-a^2)

    let t(x) = sqrt(x^2 - a^2)

    integral = 1/2( x T(x) - a^2 log( x + T(x))

    HOW do they arrive at this. Thanks
  2. jcsd
  3. Dec 5, 2008 #2


    User Avatar
    Science Advisor
    Homework Helper

    Are t and T the same?

    And have you tried using a trig or hyperbolic substitution?
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