Derive integral of sqrt(x^2-a^2)

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The integral of the function defined as sqrt(x^2 - a^2) is expressed using the formula integral = 1/2( x T(x) - a^2 log( x + T(x))). In this context, T(x) represents the same function as t(x), which is defined as sqrt(x^2 - a^2). The discussion suggests exploring trigonometric or hyperbolic substitutions as alternative methods for solving this integral.

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coverband
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Sorry me again

THE CRC tables define the above integral as

using sqrt(x^2-a^2)

let t(x) = sqrt(x^2 - a^2)

integral = 1/2( x T(x) - a^2 log( x + T(x))

HOW do they arrive at this. Thanks
 
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Are t and T the same?

And have you tried using a trig or hyperbolic substitution?
 

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