# Derive integral of sqrt(x^2-a^2)

1. Dec 5, 2008

### coverband

Sorry me again

THE CRC tables define the above integral as

using sqrt(x^2-a^2)

let t(x) = sqrt(x^2 - a^2)

integral = 1/2( x T(x) - a^2 log( x + T(x))

HOW do they arrive at this. Thanks

2. Dec 5, 2008

### morphism

Are t and T the same?

And have you tried using a trig or hyperbolic substitution?