Derived values not satisfying equations.

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The discussion centers on the derivation of values for two colliding bodies using the laws of conservation of kinetic energy and momentum. Initial calculations yielded values that did not satisfy the conservation of kinetic energy equation, prompting a review of the quadratic equation used to solve for the final velocities. After identifying and correcting errors in the calculations, the final velocities were found to satisfy both conservation equations, with one root corresponding to the initial velocity of the faster body. A "sanity check" revealed that one of the roots should match the original faster body's velocity, confirming the accuracy of the revised calculations. Ultimately, the problem was resolved, demonstrating the importance of careful error-checking in physics equations.
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I derived some values from 2 equations...the values are such that its not complying with one of the equations -

Considering scenario of 2 colliding bodies, in this case both move in the same direction but one is much faster.
u1 = 80
u2 = 500
v1 = ?
v2 = ?
m1 = 100
m2 = 10

Forming equation for law of conservation of K.E -

m1*u1^2 + m2*u2^2 = m1*v1^2 + m2*v2^2

100*6400 + 10*250000 = 100*v1^2 + 10*v2^2

640000 + 2500000 = 100*v1^2 + 10*v2^2

314000 = 10*v1^2 + v2^2...1

Forming equation for law of conservation of Momentum -
m1*u1 + m2*u2 = m1*v1 + m2*v2

8000 + 5000 = 100v1 + 10v2

13000 = 100v1 + 10v2

13000 = 100v1 + 10v2

1300 = 10v1 + v2...2

130 - v2/10 = v1

Substitute v1 in 1 -

314000 = 10*(130 - v2/10)^2 + v2^2

314000 = 10*(16900 + (v2^2)/100 - 26v2) + v2^2

31400 = 16900 + (v2^2)/100 - 26v2 + v2^2

31400 = 16900 - 26v2 + 1.01v2^2

0 = -14500 - 26v2 + 1.01v2^2

0 = 14500 + 26v2 – 1.01v2^2

By quadratic equation formula -

v2 = 107.6364125 and -133.3789860

The negative value will be correct since the body will recoil.
Taking negative value and substituting it in equation 2-

1300 = 10v1 - 133.3789860

v1 = 143.3378986

Values do not comply with conservation of K.E

Taking positive value -

1300 = 10v1 – 107.6364125

v1 = 140.7636412

Error was pointed out by jtbell...and is now fixed.
 
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dE_logics said:
314000 = 10*v1^2 + v2^2...1

130 - v2/10 = v1

Substitute v1 in 1 -

314000 = 10*(130 - v2/10) + v2^2

Do you see your error now?
 
Thanks for that man...I edited that question...and the problem still persists after correction.
 
I haven't got time to go back over the details right now, but I can suggest a "sanity check." When you solve the quadratic equation to get v2, one of the roots should equal the original u2. This corresponds to the two objects "passing through each other" without interacting, in which case the total momentum and total KE are obviously conserved.
 
I think something's wrong with the quadratic equation...the sanity check has failed.

But I don't know what's wrong.
 
Problem solved...one of my many careless errors.

Considering scenario of 2 colliding bodies, in this case both move in the same direction but one is much faster.
u1 = 80
u2 = 500
v1 = ?
v2 = ?
m1 = 100
m2 = 10

Forming equation for law of conservation of K.E -

m1*u1^2 + m2*u2^2 = m1*v1^2 + m2*v2^2

100*6400 + 10*250000 = 100*v1^2 + 10*v2^2

640000 + 2500000 = 100*v1^2 + 10*v2^2

314000 = 10*v1^2 + v2^2...1

Forming equation for law of conservation of Momentum -
m1*u1 + m2*u2 = m1*v1 + m2*v2

8000 + 5000 = 100v1 + 10v2

13000 = 100v1 + 10v2

1300 = 10v1 + v2...2

130 - v2/10 = v1

Substitute v1 in 1 -

314000 = 10*(130 - v2/10)^2 + v2^2

314000 = 10*(16900 + (v2^2)/100 - 26v2) + v2^2

314000 = 169000 + (v2^2)/10 – 260v2 + v2^2

314000 = 169000 – 260v2 + 1.1v2^2

0 = -145000 – 260v2 + 1.1v2^2

0 = +145000 + 260v2 – 1.1v2^2

v2 = 500
v2 = -263.63636363 or -2900/11
alternative -

v1 by eq. 2 = 156.3636363636363636 or 1720/11

Equations satisfied.
 
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