Deriviate proof d/dt[r (v a)]= r(v a)

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The discussion focuses on proving the derivative of the expression d/dt[r(v x a)] equals r(v x da/dt). Participants express confusion about how to start the problem and the necessary steps to simplify the equation. Key points include the importance of applying the chain rule and understanding vector properties, such as the cross product of a vector with itself being zero. The conversation emphasizes the need to manipulate the derivatives correctly to demonstrate the equality. Ultimately, the solution hinges on recognizing the relationship between the vectors involved and their derivatives.
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Hey guys, I really do not even know how to get this question started.

Homework Statement



\frac{d}{dt}[r (v x a)] = r (v x a)

the last a is supposed to have a period on top

as such it is \frac{d}{dt}[r (v x a)] = r (v x \frac{d}{dt}a)

d, v, and a are position, velocity, and acceleration

the last a, after the = sign is d/dt of a, as mentioned above






The Attempt at a Solution



I do not even know how to start...I tried doing different degrees of deriviatives of both left and right sides but, it seems like I need to get ride of one unit of /s (time).
 
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that was an epic fail on trying to use brackets...


derivative of [r (v times a)] = r ( v times a*)

a* is the derivative of a.

question asks to prove that both sides are equal.
 
Simply apply the chain rule and remember that the cross product of a vector with itself is 0, and that \vec a \cdot (\vec a \times \vec b)=0 (Convince yourself this is true, because a x b is perpendicular to a, and the dot product of a vector with another vector to which it is orthogonal, is 0)
 
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