- #1

ATY

- 34

- 1

We had the derivation of the ekman transport today in class. And what I wondered about is this:

Usually the equation for the ekman transport looks similar to this (depends on the author)

[tex] u = V_0 e^{az} cos(\frac{\pi}{4}+az) [/tex]

[tex] v = V_0 e^{az} sin(\frac{\pi}{4}+az) [/tex]

[tex] a= \sqrt{\frac{f}{2 A_z}} [/tex]

This is fine for the northern part of the earth, but what happens when I go to the southern hemisphere ? the coriolis parameter

*f*should become negative (since f is [tex] f = 2 \Omega sin(\phi) [/tex])

So I can not use the equations above. I am really confused because none of the derivations that I found talked about this. Or am I missing a really obvious point ?

best wishes

ATY