Deriving Moment of inertia for a hollow sphere

AI Thread Summary
To derive the moment of inertia for a hollow sphere, the key equation involves a double integral of the area multiplied by height, using bounds from 0 to 4πr² and 0 to r. The integral equation is set as r² + z² dz dA, leading to a calculation that results in (16πr⁵)/3. This value does not match the expected result of (8πr⁵)/9, indicating a potential error in the bounds or factors used in the integration process. The discussion suggests that referencing external resources may provide clarity on the correct approach. Understanding the integration limits and the application of the moment of inertia formula is crucial for accurate calculations.
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Homework Statement



How do you derive the moment of inertia for a hollow sphere?
I am not ending up with what i need to get which is: (8pir^5)/9

Homework Equations



I am not sure if the bounds are correct or if we need to factor something else in.

The Attempt at a Solution



A double integral of the area multiplied by the height.
for our integrals we do from 0 to 4pir^2 and the other integral is from 0 to r. The equation in the integral is r^2 + z^2 dzdA. (we get r^2 because x^2+y^2=r^2)

solving that out and get (16pir^5)/3.

plugging that in doesn't give the 2/3 we need for the moment of inertia.
 
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