Deriving Power Expression for Transverse Traveling Wave

AI Thread Summary
The discussion focuses on deriving the expression for power in a transverse traveling mechanical wave, starting from the equation P = k^2 * omega^2 * F * A^2 * (sin(kx - omega * t)^2) and simplifying it to P = Sqrt[(mu)F] * (omega)^2 * (A)^2. Participants are seeking clarification on the mathematical steps involved in this reduction, as some find the logic unclear. There is also a request for corrections to the equation formatting for better readability. The conversation highlights the importance of understanding wave mechanics and the derivation process. Overall, the thread emphasizes the need for clear mathematical communication in physics discussions.
Master J
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So in my book, it derives the expression for power in a traveling transverse mechanical wave.

P= Sqrt[(mu)F].(omega)^2.(A)^2

It reduces this from: P=k^2.omega^2.F.A^2.(sin(kx-omega.t)^2

Where all symbols are the standard ones in dealing with waves.

Could someone please go thru how it got from 2 to 1? I can't see the logic. I'm sure its obviously just basic math I am overlooking, but there may be a misprint in the derivation.

Cheers!
 
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Can you fix the equation in your threadd? I can't read the problem, sorry.
 
P=[Sqrt(uF)](w^2)(A^2)
 

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