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Deriving Vout in an inverting operational amplifier.

  1. May 12, 2012 #1
    Pls does anyone know how to derive for Vout1 and Vout3 in terms of Va and Vb for an inverting operational amplifier. Thank you.
     
  2. jcsd
  3. May 12, 2012 #2
    this is an image about the question.
     

    Attached Files:

  4. May 12, 2012 #3
    See inverting amplifier section in http://physics.usask.ca/~angie/ep316/lab7/theory.htm
     
  5. May 12, 2012 #4
    There is no Va and Vb!!! I see two input voltage. I only see Vin1 and Vin2. So you look at Vin1 and Vin2 contribute. Vout1 part due to Vin1 is -(R3/R1)Vin1. Vout1 due to Vin2 is -(R3/R2)Vin2 so the total Vout1:

    [tex] V_{out1}=-\left[ \frac{R_3}{R_1}V_{in1}+\frac{R_3}{R_2}V_{in2} \right][/tex]

    You try to do the next one.
     
  6. May 14, 2012 #5
    Thanks a lot. that really helped
     
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