Deriving Vout in an inverting operational amplifier.

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Discussion Overview

The discussion revolves around deriving the output voltages Vout1 and Vout3 in terms of input voltages Va and Vb for an inverting operational amplifier. The scope includes theoretical derivation and circuit analysis related to operational amplifiers.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant requests assistance in deriving Vout1 and Vout3 in terms of Va and Vb.
  • Another participant provides an image related to the question but does not elaborate further.
  • A third participant reiterates the request for derivation and references a specific online resource for guidance.
  • Some participants assert that there are no variables Va and Vb, instead identifying the inputs as Vin1 and Vin2, and provide a formula for Vout1 based on these inputs.
  • The formula presented for Vout1 is given as Vout1 = -[(R3/R1)Vin1 + (R3/R2)Vin2], indicating contributions from both input voltages.
  • A later reply expresses gratitude for the clarification provided regarding the derivation.

Areas of Agreement / Disagreement

Participants disagree on the identification of input variables, with some insisting on the use of Vin1 and Vin2 instead of Va and Vb. The discussion remains unresolved regarding the derivation of Vout3.

Contextual Notes

There are limitations in the discussion, including the absence of clear definitions for the input variables and potential dependencies on circuit configurations that are not fully detailed.

Sammyboss
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Pls does anyone know how to derive for Vout1 and Vout3 in terms of Va and Vb for an inverting operational amplifier. Thank you.
 
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There is no Va and Vb! I see two input voltage. I only see Vin1 and Vin2. So you look at Vin1 and Vin2 contribute. Vout1 part due to Vin1 is -(R3/R1)Vin1. Vout1 due to Vin2 is -(R3/R2)Vin2 so the total Vout1:

V_{out1}=-\left[ \frac{R_3}{R_1}V_{in1}+\frac{R_3}{R_2}V_{in2} \right]

You try to do the next one.
 
yungman said:
There is no Va and Vb! I see two input voltage. I only see Vin1 and Vin2. So you look at Vin1 and Vin2 contribute. Vout1 part due to Vin1 is -(R3/R1)Vin1. Vout1 due to Vin2 is -(R3/R2)Vin2 so the total Vout1:

V_{out1}=-\left[ \frac{R_3}{R_1}V_{in1}+\frac{R_3}{R_2}V_{in2} \right]

You try to do the next one.
Thanks a lot. that really helped
 

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