Design an Ammeter - Know How to Measure Current

  • Thread starter Thread starter cks
  • Start date Start date
  • Tags Tags
    Ammeter Design
Click For Summary
SUMMARY

The discussion focuses on designing an ammeter using a photodiode and a differential amplifier. The photodiode acts as a current source, generating a reverse photocurrent that is amplified by a current-to-voltage converter circuit. The output voltage from this circuit is then converted to current through a resistor, which is connected in series with the ammeter. The participants clarify that a closed loop is necessary for current flow, and they provide specific configurations for connecting the photodiode and op-amp to measure current accurately.

PREREQUISITES
  • Understanding of photodiode operation and characteristics
  • Knowledge of differential amplifier configurations
  • Familiarity with current-to-voltage conversion techniques
  • Basic principles of electric circuits and closed loops
NEXT STEPS
  • Research "Operational Amplifier Current-to-Voltage Converter" for detailed circuit designs
  • Explore "Photodiode Amplifier Circuits" to understand various configurations
  • Study "Inverting Amplifier Configurations" for practical applications in current measurement
  • Learn about "Vacuum Photodiode Biasing" for high-voltage applications
USEFUL FOR

Electronics engineers, hobbyists designing measurement circuits, and students studying photodiode applications in current measurement will benefit from this discussion.

cks
Messages
164
Reaction score
0
Hihi,

I put a photodiode's legs to both the input for a differential amplifier

http://en.wikipedia.org/wiki/File:Op-Amp_Differential_Amplifier.svg

Then, the voltage difference of the photodiode is amplified and its output is then connected to a resistor which is not shown in the above picture. The purpose I put a resistor is to convert the voltage output to current. Then, I connect in series of the output from the resistor to an ammeter to obtain the current. After which, the other end of ammeter is connected to ground.

May I ask, If I put one end of the ammeter to the ground and the other end to the resistor, will the system works, because from my high school knowledge of electric circuit, current flows only when a closed loop is formed, but I didn't see any closed loop here.
 
Engineering news on Phys.org
cks said:
Hihi,

I put a photodiode's legs to both the input for a differential amplifier

http://en.wikipedia.org/wiki/File:Op-Amp_Differential_Amplifier.svg

Then, the voltage difference of the photodiode is amplified and its output is then connected to a resistor which is not shown in the above picture. The purpose I put a resistor is to convert the voltage output to current. Then, I connect in series of the output from the resistor to an ammeter to obtain the current. After which, the other end of ammeter is connected to ground.

May I ask, If I put one end of the ammeter to the ground and the other end to the resistor, will the system works, because from my high school knowledge of electric circuit, current flows only when a closed loop is formed, but I didn't see any closed loop here.

The photodiode is basically a current source, not a voltage source. The light that hits it generates a reverse photocurrent, which you amplify with a current-to-voltage converter circuit. The output of that circuit is a voltage, so you measure that with a voltmeter:

http://images.google.com/imgres?img...bnw=126&prev=/images?q=photodiode&gbv=2&hl=en

.
 
Often, the photodiode is put in series with a battery (photoconductive mode) and the current measured with an opamp in the current-measuring mode. For a solid state photodiode, the reverse bias is a few volts. For example, the negative end of a battery is connected to ground, and the positive end connected to the cathode of the photodiode 9reverse biased). The anode is connected to the op-amp inverting input, and the positive input of opamp tied to ground (inverting configuration). See second illustration in (inverting amplifier)
http://en.wikipedia.org/wiki/Operat...ations#Negative_impedance_converter_.28NIC.29
Photodiode replaces Rin resistor. Choose Rf resistor so that the expected photodiode current produces about 1 volt drop across it.
If you are using a vacuum photodiode (e.g., 935), the bias is usually 50 to 100 volts (or more), and the anode is tied to the + end of battery, and the cathode (light sensitive electrode) tied to the op amp inverting input.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
6K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K