Design Board w/ TPS61032: Connecting Pins?

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For the TPS61032 design, all pins assigned for the same function, including SW, PGND, and VOUT, should be connected as specified in the datasheet schematics to ensure proper operation. It's crucial to follow recommended PCB layout patterns for DC-DC converters to optimize performance. The layout should feature wide and short traces for the main current path and power ground tracks. Alternative options like the National Instruments "Simple Switcher" series may provide useful layout examples. Properly connecting the multiple pins enhances current handling capacity and ensures reliability in the design.
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Take a look at this data sheet http://www.datasheetcatalog.com/datasheets_pdf/T/P/S/6/TPS61032.shtml" and tell me this:
There are multiple pins assigned for the same function. there are two pins for SW and three for PGND and VOUT each. Do I only need to connect one of each pins or connect them all. I'm designing a board for the first time here.

thanks

--KoZu
 
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Absolutely connect them all as shown in the datasheet schematics. And layout is very important for DC-DC converters like this, so it would be best if you could find some recommended PCB layout patterns to start with.

Have you looked at the National Instruments "Simple Switcher" series of DC-DC converts as an alternative? I think they tend to give sample 1-layer and 2-layer layout examples for those designs. Or at least do some more searching in the TI application note literature to see if you can find an example layout.
 
I did some research, looks like this isn't a very used converter, but to me it was pretty much the only one available to suit my needs, unless I want to order directly from a manufacturer in which case the shipping alone would cost ten times more than the chip itself.

So.. when I build this thing, I connect the three VOUT etc. pins together?
 
Yes, they use multiple pins to increase current handling capacity.
 
On page 13, "Layout Considerations", it says

"use wide and short traces for the main current path and for the power ground tracks."

I would interpret that as "make one wide track on the PCB connected to the three VOUT pins on the chip" and the same for the three PGND pins.
 
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