Designing a Parity Bit Circuit for Data Transmission

AI Thread Summary
A parity bit is used in data transmission to indicate whether the number of 1's in a 4-bit data set (A, B, C, D) is even or odd. The truth table shows the parity output, where P is 0 for an even number of 1's and 1 for an odd number. The logical expression for the parity bit is P = A ⊕ B ⊕ C ⊕ D, utilizing the XOR operation. A Karnaugh Map can be used to simplify the circuit design, which should ultimately minimize the number of logic gates required. Assistance is sought for creating the circuit diagram based on the logical expression.
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Homework Statement


A parity bit will be 0 if the data contains an
even number of 1’s and it will be 1 if the data contains an odd number of 1’s. If during
transmission a 1 is changed to a 0 or vice versa, then the parity check at the receiver will
fail. Determine the parity P for
4–bits of data, A, B, C, and D. You should
Determine the truth table, Karnough Map, and logical expression for P. Draw the circuit that executes the logic. Simplify the circuit to a minimum number of logic gates.

Homework Equations

The Attempt at a Solution


Would the solution just be an even parity? In that case.

Truth Table: Since it is 0 with an even number 1s, and 1 if it will has an odd number of 1s
4-bit | Parity
0000 0
0001 1
0010 1
0011 0
0100 1
0101 0
0110 0
0111 1
1000 1
1001 0
1010 0
1011 1
1100 0
1101 1
1110 1
1111 0

Karnough Map:
For AB on the column and CD on the row

-----00 01 11 10
00--0--1---0---1
01--1--0--1----0
11--0--1--0----1
10--1--0--1---0

Logical Expression:
P =A ⊕ B ⊕ C ⊕ D

Never really been taught how to come up with the circuit diagram though. Any help?

 
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Perhaps start with the logic symbol for a ⊕ gate?
 
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