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MonsterAar
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Designing a circuit from a given transfer function.
I hope you don't mind that I haven't used the default format. It doesn't lend itself well to my problem.
The original problem is as follows:
We were given a 'black box' that contained a passive circuit and we experimentally determined a transfer function for the circuit by passing through various frequencies and recording the magnitude and phase of the outputs.
This was then used to create a bode plot. This bode plot showed a pole at approximately 56Hz and a zero at approximately 1660Hz. The DC gain of the circuit is 0.064.
From this information I deduced the transfer function of the circuit to be:
[tex]H(\omega)=0.064\frac{1+j\frac{\omega}{1660}}{1+j\frac{\omega}{56}}[/tex]
The task now asks for us to design a circuit to cancel out the effects of the black box on the input signal. Basically we have to design a circuit so that when we have input-blackbox-our circuit-output, the input=output. So, I need to design a circuit with the inverse of the above transfer function.
IE. I need to design a circuit with the following transfer function:
[tex]H(\omega)=15.625\frac{1+j\frac{\omega}{56}}{1+j\frac{\omega}{1660}}[/tex]
This is where I get stuck. How do I go about designing a circuit with a DC gain of 15.625, a pole at 1660Hz and a zero at 56Hz?
I understand I'll have to use an op-amp to get the DC gain greater than 1. Other than this I'm stuck.
Thanks,
Luke
I hope you don't mind that I haven't used the default format. It doesn't lend itself well to my problem.
The original problem is as follows:
We were given a 'black box' that contained a passive circuit and we experimentally determined a transfer function for the circuit by passing through various frequencies and recording the magnitude and phase of the outputs.
This was then used to create a bode plot. This bode plot showed a pole at approximately 56Hz and a zero at approximately 1660Hz. The DC gain of the circuit is 0.064.
From this information I deduced the transfer function of the circuit to be:
[tex]H(\omega)=0.064\frac{1+j\frac{\omega}{1660}}{1+j\frac{\omega}{56}}[/tex]
The task now asks for us to design a circuit to cancel out the effects of the black box on the input signal. Basically we have to design a circuit so that when we have input-blackbox-our circuit-output, the input=output. So, I need to design a circuit with the inverse of the above transfer function.
IE. I need to design a circuit with the following transfer function:
[tex]H(\omega)=15.625\frac{1+j\frac{\omega}{56}}{1+j\frac{\omega}{1660}}[/tex]
This is where I get stuck. How do I go about designing a circuit with a DC gain of 15.625, a pole at 1660Hz and a zero at 56Hz?
I understand I'll have to use an op-amp to get the DC gain greater than 1. Other than this I'm stuck.
Thanks,
Luke
Last edited: