Determine if set is a vector space

Laura1321412
Messages
23
Reaction score
0

Homework Statement



Q) Determine if the set is a vector space under the given operations

The set of all pairs of real numbers of the form (1,x) with the operations (1,y)+(1,y')=(1,y+y') and k(1,y)=(1,ky)


2. Homework Equations / Solution Attempt

I know the axioms needed in this case, and I believe most all of them hold. The ones I am having trouble with in particular are

> There is an object 0 in V called the zero vector such that 0+u= u.
- But there isn't a zero vector if V is defined by (1,x) right?

> For each u in V there is an object -u in V, such that -u + u =0
- But -u would equal (1,-x) + (1,x) = (2,0) -- not 0


However, in the answer section of my book it says that this is a vector space under the given operations. I can't understand how the two above axioms hold... Any help is greatly appreciated!
 
Physics news on Phys.org
Laura1321412 said:
> There is an object 0 in V called the zero vector such that 0+u= u.
- But there isn't a zero vector if V is defined by (1,x) right?

> For each u in V there is an object -u in V, such that -u + u =0
- But -u would equal (1,-x) + (1,x) = (2,0) -- not 0

First: There must be a zero vector, but the only property the zero vector needs to have is that 0 + u = u + 0 = u for every u \in V -- using the definition of + you are given. In other words, you shouldn't necessarily expect the zero vector to be (0, 0). In fact, as you point out, (0, 0) \notin V.

Second: Be careful -- when you compute -u + u, what definition of + should you be using?
 
You can (and should) use the report button to request that your other thread be deleted. (I also agree with what ystael said).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top