Determine the final speed of each disk.

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In an elastic collision between two shuffleboard disks, the orange disk, moving at 4.40 m/s, strikes the yellow disk, which is initially at rest. After the collision, the disks move at right angles to each other, with the orange disk making a 38° angle with its original direction. The discussion emphasizes the need to apply conservation of momentum and energy in both x and y directions to solve for the final speeds of both disks. The equations derived from these principles lead to a complex relationship between the velocities, ultimately requiring algebraic manipulation to find the correct final speeds. The challenge lies in accurately applying these principles to avoid algebraic errors and ensure the calculations reflect the physical scenario.
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Homework Statement


Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in an elastic, glancing collision. The yellow disk is initially at rest and is struck by the orange disk moving with a speed of 4.40 m/s. After the collision, the orange disk moves along a direction that makes an angle of 38.0° with its initial direction of motion. The velocities of the two disks are perpendicular after the collision. Determine the final speed of each disk.

Homework Equations


p=mv

The Attempt at a Solution


Well I've tried conservation of momentum, and even have this link at my disposal; i just cannot get the correct answer (probably due to basic algebra errors.)
http://answerboard.cramster.com/Answer-Board/Image/200710151121116332804407123187505694.jpg

Granted that my angle is 1° off, and the speed is different; I end up with a final formula of sqrt(Uo^2-Vo^2)=Vo/tan(38)
=Uo^2-Vo^2 = (Vo/Tan38)^2
=Uo^2-Vo^2=Vo^2/tan(38)^2.
=Tan(38)^2*Uo^2-Tan(38)^2*Vo^2=Vo^2
=tan(38)^2*^Uo^2=0.6104Vo^2
=(tan(38)^2*(4.4^2))/(0.6104)=Vo^2
=19.3602=Vo^2
=4.4=Vo
Yet... that's not right, because it's the original speed and unless the yellow didn't move at all; it would be impossible. But I don't know what else to do.
 
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In an elastic collision you have conservation of momentum in two perpendicular directions and conservation of energy. Easiest to pick the initial path of the orange disk as one of the directions.

That gives you 3 simultaneous equations ...
 
In oblique elastic collision conserve momentum in x and y direction separately. And apply conservation of energy.
Orange disc is moving horizontally. So its y- componet of momentum must be zero. Hence y component of vo=vosin38, and y component of vy = vysin52. To make y component zero, they must be equal and opposite, So vosin38 = vysin52 (Since mass is same it gets canceled out.) write vy in terms of vo, and put it in the equation Vy^2 = vy^2 + vo^2 and solve for vo.And hence find vy.
 
rl.bhat said:
In oblique elastic collision conserve momentum in x and y direction separately. And apply conservation of energy.
Orange disc is moving horizontally. So its y- componet of momentum must be zero. Hence y component of vo=vosin38, and y component of vy = vysin52. To make y component zero, they must be equal and opposite, So vosin38 = vysin52 (Since mass is same it gets canceled out.) write vy in terms of vo, and put it in the equation Vy^2 = vy^2 + vo^2 and solve for vo.And hence find vy.

So Vosin38=Vysin52, Vy=(vosin38)/sin52)
Vy^2 = vy^2 + vo^2 <--- Plugging it into this
(vosin38)/sin52)^2 =(vosin38)/sin52)^2 + Vo^2
Vosin38^2 = Vosin38^2 + Vo^2sin52
Vosin38^2 -Vosin38^2 -Vosin52^2 = 0
Vo(sin38^2-sin38^2-Sin52^2)=0
Vo(Sin52^2)=0
Vo=0/(sin52^2) ??
 
(vosin38)/sin52)^2 =(vosin38)/sin52)^2 + Vo^2
In the expression Vy indicates the initial velocity of the yellow disc.
So (4.4)^2 =(vosin38)/sin52)^2 + Vo^2 Now try.
 
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