Determine the fraction of the volume

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To determine the volume occupied by 1.25 mol of an ideal gas at 310K and 101kPa, the ideal gas law (PV=nRT) is applied, resulting in a calculated volume of approximately 31882.43 m³. For the second part, the volume occupied by gas molecules, approximated as small spheres with a diameter of 2.5x10^-10 m, is calculated to be 8.18x10^-30 m³ per molecule. The total number of molecules is derived from the ideal gas law, yielding approximately 7.5275x10^23 molecules. A method to find the fraction of the total volume occupied by the molecules shows that this fraction can be determined without needing the number of moles, as it simplifies to a ratio that cancels out n. The discussion emphasizes the importance of understanding the relationship between volume, pressure, and temperature in ideal gas behavior.
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[SOLVED] Ideal Gases

Homework Statement


A gas has a temperature of 310K and a pressure of 101kPa (a.) find the volume occupied by 1.25 mol of this gas, assuming its ideal. (b.) assuming the gas molecules can be approximated as a small sphere of diameter 2.5x10^-10, determine the fraction of the volume found in part (a) that is occupied by the molecules.


Homework Equations


PV=nRT



The Attempt at a Solution


(a.) V=nRT/P
V= (1.25mol)(8.31J/mol*K)(310K)/0.101Pa
V= 31882.43 m^3

(b.)d= 2.5x10^-10
V(sphere)= 8.18x10^-30

n=PV/RT
n= (.101Pa)(31882.43m^3)/(8.31J/mol K)(310K)
n= 1.25 mol *6.022x10^23= 7.5275x10^23 molecules

do i just multiple these together and then find the fraction from the first volume?
 
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Yes, that works fine.

but notice, Vsphere/V can be determined without ever knowing n.

Since this fraction should not depend on how large your sample is, the number should "cancel out." solve for this fraction using variables (without plugging in numbers) and you will see n go away.
 
For the first part...1kPa=1x10^3[/tex]Pa <br /> and for the fraction occupied, vol.occupied by gas/vol.of sphere
 
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