Determine the unknown property of a perfect gas

AI Thread Summary
To determine the unknown property of the gas, the ideal gas equation PV=nRT is applied. The initial parameters include a 3-L container, a pressure of 300 kPa, a temperature of 700°C, and a mass of 0.66 g. The calculation attempts to find the specific gas constant 'R', but there is confusion regarding the volume, as the solution incorrectly calculates 'V' as 3.51 instead of using the given 3 L. The correct approach involves using the provided values to derive 'R', which should yield a result of 1.401 kJ/kg·K. Accurate conversions and adherence to the given parameters are essential for solving the problem correctly.
thermo15378
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Homework Statement


a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.


Homework Equations



pv=nrt

The Attempt at a Solution



(300)(v)= (.00066 kg)(8.31)(191906 k)

= 3.51


im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K
 
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thermo15378 said:

Homework Statement


a gas in 3-L container at a pressure of 300kpa and a temperature of 700 degrees celsius, and with a mass of .66 g.


Homework Equations



pv=nrt

The Attempt at a Solution



(300)(v)= (.00066 kg)(8.31)(191906 k)

= 3.51


im not sure what conversion needs to be done as the correct answer is found to be 1.401 kj/kg.K


From the information given and the answer you posted, you are to use PV= mRT to get 'R' for the gas.

In your calculation you found 'V' as 3.51 when they already gave you V=3 L.
 
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