Determing the composition of a state

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The discussion centers on determining the composition of a quantum state represented by two eigenvectors, specifically |v>=a|ω₁>+b|ω₂>. The coefficients 'a' and 'b' represent the probabilities of the eigenvalues, with the equation ||² used to calculate these probabilities. The user initially calculated a as 1/√2 and b as √(√3/2), but later confirmed that a should be 1/2 and b is (3/4)^(1/2) multiplied by an arbitrary phase factor. This clarification indicates a deeper understanding of quantum state representation.

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Sekonda
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Hey,

I have a question on determing the composition of a state of a system of composed of only two eigenvectors, the question is displayed below:

determinev.png


I initially assumed that the ket v was given by:

|v>=a|\omega_{1}>+b|\omega_{2}>

Where 'a' and 'b' are constants which will determine the probability of either state. So we know the probability of the eigenvalues of ket v are given by the coefficients a and b in the equation:

\mid <v|\hat{\Omega}|v>\mid^{2}

Where for the probability of attaining the eigenvalue ω(1) we have equation:

\frac{1}{4}=a^{4}

Though I'm not sure this is correct, it implies

a=\frac{1}{\sqrt{2}}\: ,\: b=\sqrt{\frac{\sqrt{3}}{2}}

I think I have made a mistake on my third equation...

Thanks for any help,
SK
 
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P(ω1) = |<ω1|v>|2 , so: a = 1/2 and b will be (3/4)1/2 multiplied by an arbitary phase factor.
 
Right okay, this is the other way I done it but wasn't sure which way was correct... though this answer definitely makes more sense!... obviously.

Thanks cosmic dust!
SK
 

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