Determining Frequencies that Exist in a Signal

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Kleric
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Homework Statement


Using trig identities from a calculus book or other, write out the results to the following modulations. State which frequencies exist in the signal s(t).

Homework Equations


a) s(t) = Acos(2∏f₁t) * Bcos(2∏f₂t)

The Attempt at a Solution


cos(s) * cos(t) = cos (s + t)/2 + cos (s – t)/2

s(t) = ((AB)/2)*(cos(2∏t(f1 + f2)) + cos(2∏t(f1 - f2)))

What I don't quite understand is the part that asks to state which frequencies exist in the signal. I understand that in modulation, half of the signal is shifted to the right by f2, then the other half of the signal is shifted to the left by f2. Which would make the answers f2 and -f2.

According to the answer it should be f1, f2, |f2-f1|, f1+f2.
 
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Your maths looks right.

s(t) = ((AB)/2)*(cos(2∏t(f1 + f2)) + cos(2∏t(f1 - f2)))

is similar to the sum of two waves..

= Cos(2∏Fusbt) + Cos(2∏Flsbt)

when

Fusb = upper side band frequency = f1+f2
Flsb = lower side band frequency = f1-f2
 
Kleric said:

Homework Statement


Using trig identities from a calculus book or other, write out the results to the following modulations. State which frequencies exist in the signal s(t).

Homework Equations


a) s(t) = Acos(2∏f₁t) * Bcos(2∏f₂t)


The Attempt at a Solution


cos(s) * cos(t) = cos (s + t)/2 + cos (s – t)/2

s(t) = ((AB)/2)*(cos(2∏t(f1 + f2)) + cos(2∏t(f1 - f2)))

What I don't quite understand is the part that asks to state which frequencies exist in the signal. I understand that in modulation, half of the signal is shifted to the right by f2, then the other half of the signal is shifted to the left by f2. Which would make the answers f2 and -f2.

According to the answer it should be f1, f2, |f2-f1|, f1+f2.

The answer is wrong. f1 and f2 do not exist in the product, just the sums and differences, just as you have derived.

In ordinary amplitude modulation (think radio broadcast AM), , they do, but you have what is called "double-sideband, suppressed-carrier" modulation. Think of f1 as the carrier and f2 as the modulation, then you can see why it's called what it is.