Determining frequency of sound using a calibrated cathode ray oscilloscope

AI Thread Summary
A cathode ray oscilloscope (CRO) visually displays voltage over time, allowing for the measurement of sound wave properties. To determine the frequency of sound using a CRO, one must measure the period of the wave, which is the time for one complete cycle. The frequency can then be calculated using the formula Frequency = 1/Period. To observe the sound wave, connect the oscilloscope probe to a microphone output and analyze the waveform on the display. Understanding these concepts is essential for exam preparation on wave properties.
RigidBody
Messages
12
Reaction score
0
hi, i have an exam on wave properties in a week. and i found this on the syllabus. i can't remember learning it let alone what a cathode ray oscilloscope is (an electron gun thingymajig?) my textbooks don't explain it well. so if you know how to determine the frequency of sound using a calibrated cathode ray oscilloscope, please help. :eek: :bugeye: :cool: :confused:
 
Physics news on Phys.org
A cathode ray oscilloscope is not much different from a voltmeter, except it visually displays voltage (x direction) vs. time (y direction).

Newer oscilloscopes have nice internal markers on the display, and are calibrated in a way that one can measure the period of the wave, the amount of time for one cycle of the sound wave occurs in.

Frequency = 1/period. This is how you calculate the frequency of the sound wave.
 
yay thanks
 
Hammie said:
A cathode ray oscilloscope is not much different from a voltmeter, except it visually displays voltage (x direction) vs. time (y direction).
Small typo -- voltage is on the vertical y-axis and time is on the horizontal x axis. Here's a link to a popular oscilloscope brand. You will probably recognize the instrument when you see it. To measure the period or frequency of a sound, you would connect your oscilloscope probe to a microphone output, and observe the time waveform on the 'scope display.

http://www.lecroy.com/
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top