Determining Series for g(x)=1/(1+7x)^2

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Homework Statement


Determine the series for the function g(x)=1/(1+7x)^2

Homework Equations


______∞___________________∞
1/(1-x)=∑ x^n and 1/(1-x)^2=∑nx^(n-1)
______n=0________________n=1

The Attempt at a Solution


I tried to apply those equations as best I could because for the last problem, I found that
1/(7+x)=(-1)^n*7^n*x^n but I couldn't get the right answer. Any help would be appreciated
 
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This is can be written as a binomial series. Take a look at your formulae for that. If you are not familiar with these, let us know.
 
we've never gone over anything called binomial series. please elaborate or simplify!
 
could someone please explain how to do this the binomial series way, I've never learned it
 
You can start with (1-x)^{-1}, differentiate once, and make an appropriate substitution (i.e. y = -7x).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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