Determining the radius of a concentric circle.

  • Thread starter Thread starter angela107
  • Start date Start date
  • Tags Tags
    Circle Radius
AI Thread Summary
A concentric circle consists of two circles with the same center but different radii. The discussion centers on determining the radius of a smaller circle that has an area equal to half that of a larger circle, referred to as a pie. The area formula, πr², is applied to derive the radius of the smaller circle as r = √(0.5A/π). However, participants point out the confusion in using the symbol 'r' for both circles and suggest using 'R' for the larger circle's radius for clarity. Ultimately, the correct expression for the smaller circle's radius should be in terms of the larger radius R, not the area A.
angela107
Messages
35
Reaction score
2
Homework Statement
If two people were to have a pie, cut concentrically, what would the radius of the smaller disk be, such that the two individuals will have equal amounts of pie?.
Relevant Equations
n/a
1600278060979.png

A concentric cirlce has two circles with the same center, but a different radii.
We are given a pie with radius ##r##. A circular cut is made at radius ##r## such that the area of the inner circle is ##1/2## the area of the pie.

We know that the formula to calculating the area of a circle is ##πr²## or ##a=πr²## where ##a=1/2A##. Using substitution, we can determing a radius that will provide equal amounts of pie.

##0.5A=πr²##

##r²=0.5A/π##

##r= √(0.5A/π)##

Therefore, the two people will have an equal amount of pie if the radius ##r## of this smaller disk is equal to ##√(0.5A/π)##.

Can someone confirm if my work is correct?
 
Physics news on Phys.org
What you write is confusing because you have used the symbol r to mean two different things. You said,"We are given a pie with radius r. A circular cut is made at radius r such that the area of the inner circle is 1/2 the area of the pie." So you used r for both the larger radius and the smaller radius. Why don't you call the radius of the whole pie R? I think your work is correct, but I think your should express your final answer for r in terms of R, and not in terms of the area A. If you do that, what do you get?
 
  • Like
Likes Lnewqban
Assuming that A stands for area of the whole pie, do you need to know A in order to determine r?
Could you make r a function of R only, which is the easiest dimension to know?
 
angela107 said:
Therefore, the two people will have an equal amount of pie if the radius ##r## of this smaller disk is equal to ##√(0.5A/π)##.
This is correct, but you should give r in terms of the radius of the pie, which others in this thread are labelling R.
 
  • Like
Likes Lnewqban
phyzguy said:
What you write is confusing because you have used the symbol r to mean two different things. You said,"We are given a pie with radius r. A circular cut is made at radius r such that the area of the inner circle is 1/2 the area of the pie." So you used r for both the larger radius and the smaller radius. Why don't you call the radius of the whole pie R? I think your work is correct, but I think your should express your final answer for r in terms of R, and not in terms of the area A. If you do that, what do you get?
Sorry, I didn't notice I had two different R's! I will make a correction. Thank you :)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top