Diameter and Fundamental Frequency

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SUMMARY

The discussion focuses on calculating the fundamental frequencies of two open tubes with equal lengths of 1 meter but differing diameters of 1 cm and 10 cm. The relevant equation for determining the critical mode is N(Critical Mode) = L(Length) / D(Diameter). The user attempted to apply this equation in conjunction with the frequency formula f = nV/2L, but did not achieve the correct results. Additional resources were referenced for further understanding of frequency as a function of pipe diameter correction.

PREREQUISITES
  • Understanding of wave mechanics and sound frequency
  • Familiarity with the equations for open tubes and fundamental frequency
  • Knowledge of end corrections in acoustics
  • Basic mathematical skills for solving equations
NEXT STEPS
  • Research the impact of diameter on the fundamental frequency of open tubes
  • Study the concept of end corrections in acoustics for open organ pipes
  • Explore the relationship between critical modes and frequency calculations
  • Learn about the speed of sound in different mediums and its effect on frequency
USEFUL FOR

Students studying acoustics, physics educators, and anyone involved in the design or analysis of musical instruments utilizing open tubes.

mtreichl
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Homework Statement


Two open tubes both have actual length 1m but their diameters are D=1 cm and D=10 cm. Alowing fro end corrections, what are their fundamental frequencies?


Homework Equations



the only equation in my book that deals with Diamter is N(Critical Mode)=L(Length)/D(Diameter) I tried using this to find a mode to plug into f=nV/2L but that did not get me the right answer.

The Attempt at a Solution

 
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