Did I solve the hanging cable problem correctly?

  • Thread starter Thread starter physwizard
  • Start date Start date
  • Tags Tags
    Cable
AI Thread Summary
The discussion revolves around solving the hanging cable problem using the calculus of variations to minimize potential energy, resulting in the catenary equation. The user encountered issues fitting the equation to the boundary conditions, specifically y=0 at x=0 and y=a at x=a, leading to imaginary values for constants. Research indicated that others who set the lowest point of the curve as the origin did not face similar problems. The user questions whether their choice of origin affects the outcome and suggests that the boundary conditions might need adjustment. Additional boundary conditions are necessary to solve for constants a and c effectively.
physwizard
Messages
153
Reaction score
0
guys i got bored so i decided to try to solve the hanging cable problem - a cable suspended between two arbitrary points. i used the calculus of variations and the functional derivative to minimize the potential energy. i did get the catenary equation, y = a*cosh(x/a+b) + c . for some reason, it does not seem to fit the boundary conditions - y=0 at x=0, and y=a at x=a, i.e. you get imaginary values for the constants. (my origin is at the first point of suspension and here it is assumed that both points are at an equal height above the ground and x-axis is parallel to the ground and passes through the second point of suspension as well). I googled this problem and found that people who solved the problem by keeping the lowest point of the curve as the origin didn't run into the kind of problem i ran into. fundamentally, the choice of origin should not really matter. so did i do something wrong?
 
Physics news on Phys.org
I would guess your boundary conditions should be y=0 at x=0 and y=0 at x=a, right?
Then you can solve for b=-1/2 and determine the ratio c/a to equal cosh(-0.5).
To get a or c, you'd need another boundary condition.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top