Diff EQ Repeated Complex Eigenvalues?

th3ownly
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1. What dimensions of a matrix will give repeated complex Eigenvalues? Give an example
of one and show that it has repeated complex Eigenvalues.


2. No really equations needed?


The Attempt at a Solution



My attempt is a 2x2 which i don't think is right but here it is.

If the matrix were
we will use x as lambda

(x)' = [2+3i - λ 0 ] (x)
(y) ' = [ 0 2+3i-λ] (y)
This would yield the eigenvalues 2+3i, 2+3i


I just don't think my solution is right
 
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If you mean the matrix [[2+3i,0],[0,2+3i]] has a double complex eigenvalue of 2+3i, I don't see what could be wrong with that.
 
Why do you think it doesn't? In order for a non-trivial solution det(A-λI) = 0 right?

Do it out -- does that equation ever equal zero?

However I think there is a better way to go about doing this you've simply listed a property of a 2x2 matrix where the eigenvalues will be the diagonal elements as long as everything else is 0.

The characteristic equation of a 2x2 matrix:

[A-λ, B]
[C, D-λ]

Is a quadratic, right?

How do we know if the roots will be imaginary from looking at the characteristic equation?
 
Feldoh said:
Why do you think it doesn't? In order for a non-trivial solution det(A-λI) = 0 right?

Do it out -- does that equation ever equal zero?

However I think there is a better way to go about doing this you've simply listed a property of a 2x2 matrix where the eigenvalues will be the diagonal elements as long as everything else is 0.

The characteristic equation of a 2x2 matrix:

[A-λ, B]
[C, D-λ]

Is a quadratic, right?

How do we know if the roots will be imaginary from looking at the characteristic equation?

necause there is no sign change?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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