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Diffentiation and integration in electronic circuit

  1. Jul 11, 2012 #1
    greetings,

    how a inductor and capacitor can perform differentiation and integration respectively?
    any help would be appreciated .
     
  2. jcsd
  3. Jul 11, 2012 #2
    Do you know that for an inductor the induced voltage is proportional to the rate of change of current?
    Usually written as E = L.di/dt. This means that E is proportional to the gradient of an i against t graph. This is a basic picture of differentiation.
    For a capacitor the charge on a capacitor is the product of current x time. This means that charge is proportional to the area under a graph of i against t. This is the basis of integration.
    The voltage across a capacitor is proportional to the charge (V = Q/C) and this is usually written as V =1/C ∫i.dt
     
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