Linear Dependence of Functions with Absolute Value

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Homework Statement


Determine whether the pairs of functions are linear dependent or linearly independent.

f(x) = x^3
g(x) = x2|x|

Homework Equations





The Attempt at a Solution



g(x)=x^2|x| = x^2*sqrt[x^2] = sqrt[x^6] = x^3

f'=3x^2
g'=3x^2

fg'-f'g = 0

Linearly Dependent according to me, Linearly independent according to the book.

I assume it has to do with the absolute value, could someone enlighten me?
 
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Should g'(x) be 2x|x|+x^2(|x|/x) ?
 
note that f is positive for some values of x and negative for others whereas g is always positive. if these two were linearly dependent one would be a constant multiple of the other FOR ALL VALUES OF x. can we multiply a fully positive function by a number so that part of it becomes negative? no. therefore no linear dependence. note also this depends on the set over which g and f are defined.
 
why are you take the derivative?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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