Difference between coefficient of static and kinet friction

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Discussion Overview

The discussion centers on the differences between the coefficients of static and kinetic friction, particularly in the context of a block on a horizontal surface connected to a pulley with a hanging weight. Participants explore the conditions under which static and kinetic friction apply, and the implications of these forces on the motion of the block.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant proposes that if a block is not moving, the force applied equals the force of static friction, leading to the conclusion that the coefficient of static friction can be expressed as the ratio of the masses involved.
  • Another participant challenges this by stating that the static friction coefficient indicates the maximum static friction force, which can vary between 0 and that maximum value, depending on the situation.
  • A question is raised about whether the equation mg = ffs holds true only when the block is just starting to move.
  • It is clarified that while mg = ffs can hold, the relationship ffs = μsN does not apply until the maximum static friction is reached.
  • Participants acknowledge that static friction can be less than its maximum value before motion occurs, depending on the applied forces.

Areas of Agreement / Disagreement

Participants express differing views on the application of static friction equations and the conditions under which they hold true. There is no consensus on the interpretation of the static friction force in relation to the applied forces.

Contextual Notes

The discussion highlights the nuances of static versus kinetic friction, including the conditions under which each applies and the definitions of the coefficients involved. There are unresolved assumptions regarding the specific scenarios being analyzed.

bookerdewitt
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Lets say you have a block on a horizontal surface connected to a pulley and then a weight hanging over the edge. If its not moving then the force applied which is just the mass of the weight x gravity is equal to the force of static friction μsmblockg. So that means μs = the mass of the weight/the mass of the block. But if the block is moving at a constant velocity wouldn't the force applied also equal the force of kinetic friction which would mean the μk also equals the ratio of the masses? I thought the coefficient of static friction is always higher than the coefficient of kinetic friction? Where am I going wrong?
 
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bookerdewitt said:
If its not moving then the force applied which is just the mass of the weight x gravity is equal to the force of static friction μsmblockg.
No. The static friction coefficient tells you the maximal static friction force, for a given normal force. The actual static friction force can be anything between 0 and that value.
 
So mg=ffs would only hold if the block is just starting to move?
 
bookerdewitt said:
So mg=ffs would only hold if the block is just starting to move?

Yeah, dude. The expression for static friction is Fs μsN, where N is the normal force, and μs is the coeff. of static friction. So, μsN is the maximum static friction that can be provided. Anytime before the maximum static friction is overcome and the object starts moving, the static friction force is less than that, because it is only whatever value it needs to be to prevent motion, given the other applied forces on the body.
 
No. mg=ffs would hold but ffs = mu * N wouldn't.
 
Ok. That makes sense.
 

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