Difference between f '(2x) and [f(2x)] ' ?

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Homework Help Overview

The discussion revolves around the differentiation of functions, specifically comparing f '(2x) and [f(2x)] '. Participants are exploring the implications of these expressions in the context of calculus.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify the difference between the two expressions, with some providing examples to illustrate their points. Questions about the notation and its interpretation in Leibniz form are also raised.

Discussion Status

The discussion is active, with participants providing insights and examples to differentiate the two expressions. There is a mix of agreement and differing opinions regarding the interpretation of the notation used, indicating a productive exploration of the topic.

Contextual Notes

Some participants express uncertainty about the notation and its implications, suggesting that there may be ambiguity in how derivatives are represented in different contexts.

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Homework Statement


What is the difference between f '(2x) and [f(2x)] ' ?

If we integrate, is there any difference between
∫ f '(2x) dx and ∫ [f(2x)] ' dx?

Homework Equations


N/A

The Attempt at a Solution


N/A

Can someone please explain? I would really appreciate!:smile:
 
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[f(2x)]' is the derivative of the function f(2x)

f'(2x) is the derivative of the function f(x) applied at the point 2x. An example may help:

f(x) = sin(x). Then f'(x) = cos(x). So f'(2x) = cos(2x)

On the other hand, f(2x)= sin(2x) So [f(2x)]' = 2cos(2x).
 
How would you write that in Leibniz notation?
 
I've often seen it written as:

f'(2x) = \frac{df}{dx} \Big |_{2x}

The vertical bar meaning 'evaluated at'. So this is the derivative of f evaluated at the point 2x. For the other case

[f(2x)]' = \frac{d[f(2x)]}{dx}
 
So you wouldn't write
<br /> \frac{d\,f}{d\;2x}<br />
??
 
Office_Shredder said:
I've often seen it written as:

f&#039;(2x) = \frac{df}{dx} \Big |_{2x}
I don't agree. It seems to me that the prime on the left means "take the derivative with respect to the argument", and the argument is 2x; the d/dx on the right means "take the derivative with respect to x".

Ambiguity is removed via

f&#039;(2x) = \frac{df(y)}{dy} \Big |_{y=2x}
 

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