RedX said:
I find that interesting, but I'm not sure I follow. How do particles transform through their gauge group as they propagate in time?
That is what the gauge potential (affine connection) determines.
D_\mu = \partial_\mu + iW_\mu
Don't hypercharge and weak isospin combine because choosing a vacuum state preserves the symmetry of transformations generated by that particular combination of generators?
Yes, but the reason that this choice of vacuum doesn't preserve ALL the gauge groups is the breaking of the symmetry (for the ground state=vacuum) via e.g. the Higgs mechanism which determines the inertia of the physical particles.
In the discussion here people keep speaking of "no momentum for stationary particles" which is not correct in the relativistic setting where momentum -> momentum-energy.
Here's a more concrete analogue. Consider light moving through a transparent material. The coupling of light to the matterial gives the photons an effective mass and they travel at less than c. This effective mass can be seen as coming from the inertia of the charge carriers of the material (it's inertia) to the e-m field of the light.
Now break the symmetry (in this case rotation sym), consider a birefringent crystal. Since the crystal couples differently to different photon polarizations you get different effective masses for the two transverse polarizations relative to the crystal alignment. The vertical photons and horizontal photons, while in this crystal behave like distinct types of particles with different masses.
This is an imperfect analogue since one is breaking a non-gauge symmetry but I think it shows some of the features.
So for example although W1 and W2 don't have a definite charge, W^{\pm}=W^1 \pm i W^2 do have definite charge, and you're saying this is only because W^{\pm} have definite mass/are the mass eigenstates? I'm troubled by that imaginary combination, but don't W1 and W2 have the same mass anyway, so that any linear combo would also have the same mass?
You have the W^1, W^2 and W^3 modes of the SU(2) gauge field, or in a different basis W^{\pm},W^0. Each modulo iso-rotations.
In the absence of symmetry breaking we'd have a continuum of superpositions of weak bosons, each massless, as well as massless hyper-photons. Apply the Higgs field, which creates a non-trivial weak-isospin-hypercharge vacuum. As with the analogue of the birefringent crystal, the masses of the gauge bosons are no-longer exactly zero but one has a mass matrix. In its eigen-spaces we have W^{\pm} (realtive to a particular isospin direction I_z) and we have the photon and the weak boson Z_0 as superpositions of the hyper-photon and W^0 boson fields which have respective 0 and non-zero "eigen-masses".
This also causes the leptons to split into heavier electrons/muons/tauons, vs lighter neutrinos.
Also, what gauge group corresponds to neutrino oscillations, if it's inertia that corresponds to failing to align to gauge charges?
This is a bit more strained but one supposes a separate SU(3) flavor mixing "symmetry" manifesting at a much higher energy. It breaks in a similar fashion as above giving e.g. electrons, muons, and tauons different masses. There is a distinction since we do not see manifest gauge bosons for the flavor group (unless this broken SU(3) is restored inside the nucleon somehow and it is the same as the color gauge...wild speculation there!)
But ultimately for neutrinos to oscillate they must a.) have masses and b.) the eigen-masses must be superpositions of the flavors identified with the quarks and non-neutrino leptons. In other words the mass matrix for one half of the weak doublets must be different slightly than for the other half of the weak doublets. The flavor spectrum which gives eigen-masses for electrons, muons, and tauons must not quite give eigen-masses for the corresonding neutrinos. So as these propagate they must oscillate through the flavors. This oscillation is at the "beat frequency" for their distinct phase frequencies given momentum is conserved but masses are distinct.