Different answer from teacher's .

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The discussion centers on a discrepancy between a student's calculation of the charge magnitude on two equal but opposite point charges and the answer provided by their teacher. The student calculated a charge of 4.98 x 10^-9 C using the electric field and force relationship but received a different answer of 6.2 x 10^-10 C from the teacher. A key point raised is that the student may have misapplied the formula by using a test charge, as the electric field at the midpoint is a result of the two point charges rather than a single charge's effect. It is suggested that the student review the derivation of the electric field for point charges and consider that the teacher's method may differ. Clarification from the teacher is recommended to resolve the confusion.
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different answer from teacher's...

Okay, here's what the question says in my book: The electric field midway between two equal but opposite point charges is 1750 N/C, and the distance between the charges is 16.0 cm. What is the magnitude of the charge on each?
I found what the force would be equal to and put it in place of F in E=F/q. When I worked it out I got 4.98 x 10^-9 C but the answer my teacher gave us was 6.2 x 10^-10 C. So am I not getting it or did he give the wrong answer? Any help would be much appreciated, thanks!
 
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dncnqn said:
Okay, here's what the question says in my book: The electric field midway between two equal but opposite point charges is 1750 N/C, and the distance between the charges is 16.0 cm. What is the magnitude of the charge on each?
I found what the force would be equal to and put it in place of F in E=F/q. When I worked it out I got 4.98 x 10^-9 C but the answer my teacher gave us was 6.2 x 10^-10 C. So am I not getting it or did he give the wrong answer? Any help would be much appreciated, thanks!


Er... what "force" are you calculating? The force exerted on one by the other? How could you know this? All you are given is the electric field at the midway point. There's NO charge here for you to use for the "q" in F=qE. Both of the charges given combine to produce the "E". None of them can be used as a "test charge" anymore for you to use as "q". They are both the SOURCE of the electric field.

Look up (or derive) the expression of the E-field for a point charge. You have two point charges. The electric field at the midway point for your problem is the superposition from each of them. In fact, since the point is on a line between these two, and the E-field from each points in the same direction, the E-field from the individual charges ADDS.

Zz.
 


It's possible that your teacher may have made a mistake in their calculation or used a different method to find the answer. It's always important to double check your work and make sure all the steps are correct. If you're still unsure, it's always a good idea to ask your teacher for clarification or to go over the problem again in class. Sometimes there can be multiple ways to solve a problem and it's important to understand all the different approaches. Keep up the good work and don't be afraid to ask for help when needed!
 
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