1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Different solutions to x/(1-x) by substitution and decomposition

  1. Mar 5, 2014 #1
    1. The problem statement, all variables and given/known data

    Derive x/(1-x)

    2. Relevant equations

    By substitution:
    u = (1-x)
    du = -dx
    ∫x/(1-x)dx = -∫(1-u)/u du = ∫1-(1/u)du = u-log(u)+c = (1-x) - log(1-x) + c

    By decomposition:
    x/(1-x) = 1/(1-x)-1
    ∫1/(1-x)-1dx = -log(1-x)-x+c

    3. The attempt at a solution
    Which solutions should I use (1-x) - log(1-x) + c or -log(1-x)-x+c, or are both equally good?
     
  2. jcsd
  3. Mar 5, 2014 #2

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    You are integrating, not 'deriving'. But they are both correct. Take the derivative of both and see if they reduce to x/(1-x). They only differ by the constant 1.
     
    Last edited: Mar 5, 2014
  4. Mar 5, 2014 #3
    Sorry, I meant to say "integrate". Thanks for the response though.
     
  5. Mar 6, 2014 #4
    As Dick said, both are correct. A trick that will help you in the future is to combine constants. In this case you have 1 + c. Since both are constants you can combine this into a new constant c' = 1+c. Then since the label of the constant is arbitrary, you can call this new constant c, and both answers are the same. Combining constants works for any operation so two constants multiplied together can be combined into a single constant, etc.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Different solutions to x/(1-x) by substitution and decomposition
Loading...