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Differentiable everywhere

  1. Jan 31, 2007 #1
    f(x)= x^4 x less than or = 2
    mx+b x is greater than 2

    Find the values of m and b that make f differentiable everywhere.

    so what i was trying to do was to find where the graph of x^4=mx where x=2 so that the mx+b function would start at where ever x^4 left off at x=2

    i got m=8 and b=0.....but that is not right....please tell me what i am doing wrong
     
  2. jcsd
  3. Jan 31, 2007 #2

    mathman

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    At x=2:
    x4=16
    4x3=32

    Therefore:
    2m+b=16
    m=32
    resulting in b=-48.
     
  4. Jan 31, 2007 #3
    thank you so much!
     
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