Differentiable everywhere

  • Thread starter Rasine
  • Start date
  • #1
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Main Question or Discussion Point

f(x)= x^4 x less than or = 2
mx+b x is greater than 2

Find the values of m and b that make f differentiable everywhere.

so what i was trying to do was to find where the graph of x^4=mx where x=2 so that the mx+b function would start at where ever x^4 left off at x=2

i got m=8 and b=0.....but that is not right....please tell me what i am doing wrong
 

Answers and Replies

  • #2
mathman
Science Advisor
7,771
419
At x=2:
x4=16
4x3=32

Therefore:
2m+b=16
m=32
resulting in b=-48.
 
  • #3
205
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thank you so much!
 

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