f(x)= x^4 x less than or = 2(adsbygoogle = window.adsbygoogle || []).push({});

mx+b x is greater than 2

Find the values of m and b that make f differentiable everywhere.

so what i was trying to do was to find where the graph of x^4=mx where x=2 so that the mx+b function would start at where ever x^4 left off at x=2

i got m=8 and b=0.....but that is not right....please tell me what i am doing wrong

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# Differentiable everywhere

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