- #1

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I can see [tex]\frac{d\Theta}{d\theta}[/tex]=[tex]\frac{dP}{du}[/tex] for the far RHS but can't get the 1-u[tex]^{2}[/tex] to come out. I don't really remember how to do this though I'm sure I have been able to at some point so a starting tip would be much appreciated! The main trap I keep falling in is the temptation to try something with chain rule to get rid of all those d[tex]\theta[/tex] bits in the original equation. I know I'm not supposed to as I'm just supposed to be substituting, not solving, but I'm not sure how else to go about it.