Differential Equation first order help

[mlazos]

Can anybody tell me what can be the solution of this differential equation?

(dr/dt)^2=a/r^2+b/r+c
Is first order and i need some ideas about solving it

 

[StatusX]

What have you tried? I'd suggest starting by multiplying both sides by dr/dt, and trying to get each side into the form d/dt(something).

 

[arildno]

This is a separable diff.eq. You may rewrite it as:
\frac{rdr}{\sqrt{a+br+cr^{2}}}=\pm{dt}
This can be readily integrated, yielding an implicit equation for the function r(t).

 

[mlazos]

you are right,
the answer was obvious.i guess i need to rest a little. thank you guys.

 

[arildno]

As a hint, you ought to rewrite the left-hand side as:
\frac{rdr}{\sqrt{cr^{2}+br+a}}=\frac{dr}{2c}(\frac{2cr+b}{\sqrt{cr^{2}+br+a}}-\frac{b}{\sqrt{cr^{2}+br+a}})

 

[StatusX]

Sorry, I thought that was d^2/dt^2.