Differential Equation Method OF UNDETERMINED COEFF

FahimP
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Homework Statement


I hav been trying to solve this differential equation by Method of Undetermined Coefficients for a long time.

y"-2y'-3y=-3te^(-t) ......

We are supposed to guess a solution then differentiate and go from there. I guessed
y = (At + B)e^(-t) .... but this does not work. ... can someone help me on this ... I have also tried y = Ae^(-t) but this also doesn't work. Is it possible the book answer is wrong ?


Homework Equations





The Attempt at a Solution

 
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You first need to solve the homogeneous equation. What solution do you get to that?
 
FahimP said:

Homework Statement


I hav been trying to solve this differential equation by Method of Undetermined Coefficients for a long time.

y"-2y'-3y=-3te^(-t) ......

We are supposed to guess a solution then differentiate and go from there. I guessed
y = (At + B)e^(-t) .... but this does not work. ... can someone help me on this ... I have also tried y = Ae^(-t) but this also doesn't work. Is it possible the book answer is wrong ?

Of course it's possible the book is wrong. It is also possible that you are wrong. You shouldn't have to "guess" what to try if you have the complementary solution.

I suggest you re-check your work for Ae-t. And if you get an answer you can always check it for yourself by plugging it into the DE.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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