- #1

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Show that y=(1/4)tsin2t satisfies equation

d

^{2}y/dt

^{2}+4y=cos2t

Find the general solution and deduce the solution which satisfies y(0)=0 and y'(0)=0. What happens as t increases?

Solution

In the end I stay with:

y=Acos2t+Bsin2t+(1/4)tsin2t

dy/dx=-2Asin2t+2Bcos2t+(1/2)tcos2t+(1/4)sin2t

After applying boundary conditions I get:

0=0

What does it mean and what happens as 't' is increasing? I was asked to plot a graph.